4x^2+54x+155=0

Solution for 4x^2+54x+155=0 equation:

4x^2+54x+155=0

a = 4; b = 54; c = +155;
Δ = b2-4ac
Δ = 542-4·4·155
Δ = 436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{436}=\sqrt{4*109}=\sqrt{4}*\sqrt{109}=2\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-2\sqrt{109}}{2*4}=\frac{-54-2\sqrt{109}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+2\sqrt{109}}{2*4}=\frac{-54+2\sqrt{109}}{8}
$